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Limiting reactants

Suppose 358 g aluminum sulfide react with 124 g water.

Al2S3 + H2O -> Al(OH)3 + H2S unbalanced!

What mass of the excess reactant remains?

Solution Preview

Balanced equation:
Al2S3 + 6H2O -> 2Al(OH)3 + 3H2S

Molecular wt of aluminium sulphide = 2*27+3*32 = 150
Molecular wt of water = ...

Solution Summary

The answer is given step-by-step equationally.

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