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Calculating how many moles are present in a solution.

How may moles of ions are present in 500 mL of a 0.400 M solution of aluminum sulfate, (Al2(SO4)3)?

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Al2(SO4)3 when dissolved in water turns into an ionic species since its an ionic compound that is soluble in water and so it will yield AL+3 and SO4-2.

Since we have 2 AL+3 ...

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Solution and explanation. 130 words.