H2O2 + MnO2 + H+ → Mn+2 + O2 + H2O
First, we have to find the two half-reactions:
MnO2 + 4H+ + 2e- → Mn+2 + 2H2O (E = 1.23 V)
O2 + 2H+ + 2e- → H2O2 (E = 0.682 V)
Of course, the second reaction needs to be switched around. When we do, we ...
Using the electrode potentials in appendix C3 of your text, calculate the voltage for a standard cell using the following reaction.