Propene reacts with hydrobromic acid to yield 2-bromopropane via Markovnikov addition about the double bond of the alkene. The organic halide then reacts with 2-propanone(acetone), Mg metal and hydrochloric acid via Grignard reaction to yield 2,3-dimethyl-2-butanol. Write the chemical equations for these reactions using line drawings to represent the organic compounds (there are only three structures and two equations). If you are given 1.00 mol of propene and 1.25 mol (excess) HBr, a 79.0% yield would give you how much 2-bromopropane? If the calculated amount of 2-bromopropane above is combined with excess acetone, excess Mg metal and excess acid as a work-up, how much 2,3-dimethyl-2-propanol would you expect from an 83% yield?
For the first reaction we see that it is a 1:1 mole ratio for the reactants, and therefore we will make 0.79 moles of our product ...
This solution is provided in 94 words. It discusses the yield of the reaction, and provides both PowerPoint and Adobe Reader files that include drawings of the structures and the reaction.