Reagent used to add a substituent to a nitrobenzene ring

Related BrainMass Solutions

• Rate of Electrophilic Substitution

  The third cartoon is applicable to nitrobenzene where the -N=O in nitro group is in conjugation with the benzene ring and thus causes electron withdrawing resonance effect.

• Aromatic compounds - Chlorination of Nitrobenzene

  Hence chlorination of nitrobenzene proceeds slower than benzene. Again Nitro group is a meta directing group hence you will get meta chloro nitrobenzene. So it occurs slower than benzene and primarily gives m-chloronitrobenzene.

• Aromatic compounds and Nitration

  anisole will react fastes as anisole has a methoxy group attached to the benzene ring which makes the benzene ring electron rich or in a word more prone to undergo electrophilic substitution. since methoxy group has an electron releasing +R effect.

• Determining Compounds With and Without Spectroscopy

  If it's symmetrically split then we've got a 1,4-disubstituted benzene. If it's a big awkward looking, then we've probably got a 1,2-disubstituted ring. I'll leave that up to you to figure out.

• Metals Covalently Bonded to Benzene

  In a addition to its basicity, it is also a good nucleophile (a reagent that has an attraction for positive charges). It is commonly used in reactions involving attack on the carbonyl (C=O) group.

• Nitartion of ferrocene not possible why ?

  According to the mech of acelation (acetyl group first add to the ring to form an cation then H eliminate to regenerate the double bond), it is easier for the higher e.d. ring to be substituted (because of the higher nucleophilicity of the ring or can

• Groups on a benzene ring

  Activating groups have a net electron-donating effect to the ring. 2. A substituent is said to be deactivating if its presence leads to an electrophilic aromatic substitution reaction that is slower than that of unsubstituted benzene.

• Acid and Base Solution Solubility/Reaction

  The hydroxyl group donates its proton to the base forming the anion. The C10H7 group represents the two ring system of the aromatic naphthol.

• Determining the best nucleophile for aromatic substitution

  Even though it can resonance-stabilize itself, it still activates the ring, and the presence of a methyl substituent activates the ring, as well. Therefore, compound 4 should be most amenable to the reaction.