The high temperature pulping/digesting of wood generates methanoic, ethanoic, benzoic, and butanoic acids in solution. It is believed that under higher temperatures, these organic acids volatilize to their aldehyde or alcohol equivalents such as methanol, formaldehyde, benzene, butane etc. etc.
Could you explain why carbonate, specifically sodium carbonate (Na2CO3) would be particularly good at neutralizing these acids and their conjugate bases?
What would be the balanced neutralization/equilibrium equations for each of these acids in water plus sodium carbonate?
for example....CH2O2 + H2O + Na2CO3 = ?
Please walk me through the balancing of the equations and why carbonate chemistry might be particularly good in this case??
The solution examines neutralization or organic acids such as methanoic, ethanoic, benzoic, and butanoic acids with carbonate chemistry.