a. 15.00 ml of .200 M CH3COOH Ka = 1.8 x 10^-5.
b. 36.0 ml of .100 M malonic acid, (H2M) (Ka1 = 1.42 x 10^-3, ka2 = 2.01 x 10^-6
This solution explains in 680 words how to determine pH in the reaction between an acid and a base by describing the relationship between an acid and a base. Calculations of molarity, concentration and pH are completed and attached in a .doc file.