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Molecular Formula for the Oxide of Phosphorous

Determine the molecular formula of the oxide of phosphorous when it is in its gaseous state.

Temp 200C, pressure 760mmHg, mass 0.568g, volume 99.5cm3

Solution Preview

We know that PV=nRT
P=1 atm (760 mmHG is 1 atm)
V=0.0995 L (99.5 cm3=99,5ml=0.0995 L)

We need n (moles)
So n= PV/RT ...

Solution Summary

The solution involves calculations of moles using the gas law, and a subsequent calculation of molar mass.