Potassium chlorate, KClO3, decomposes when heated:
KClO3 (s) ® KCl (s) + 3/2 O2 (g)
1.00 gram of potassium chlorate is completely decomposed and the oxygen is
collected over water at 25°C and 0.99 atm. Calculate the total volume of gas
collected. (The vapor pressure of water at 25°C is 23.8 torr).
KClO3 -----> KCl + 3/2 O2
Let's multiple the whole equation by "2" to get rid of the 3/2 in front of the O2.
2 KClO3 -----> 2 KCl + 3 O2
That is easier to look at.
We start with 1.00 g of KClO3. In order to find out how much oxygen gas is released, we need to convert 1.00 grams into moles, and then use the moles of KClO3 to figure out how many moles of oxygen gas should be ...
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