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The law of Charles & Gay-Lussac

We wish to double the volume of a gas held at constant pressure. To what temperature must we heat it if its original temperature was (a) 0^oC, (b) 100^oC, and (c) 1000^oC?

I believe the answer is a) 546 K, b) 746 K and c) 2546 K. I need to see each step and formula to solve this question.

Solution Preview

PV = nRT

Assuming that 'n' is constant,

PV/T is a constant.

For a constant pressure process, V/T is a constant

Let the initial temperature and volume ...

Solution Summary

Precise solution is provided showing each step involved.