Given the standard heats of formation for the following compounds, calculate the change H2 degrees 98 for the following reaction:
CH4 (g) + H2O (g) >>>>>> CH3OH (l) + H2 (g)
Change in H Degree F (kj/mole) -75 -242 -238 0
I need to see how to solve this, and most importantly, the answer.
Delta H for the reaction is = heats of formation of ALL products - heats of reaction of ALL reactants.
The solution provides the answer and briefly describes the formula.