I am trying to find deltaH. The activation energy is 128kJ for this reaction. The activation energy for the reverse reaction is 95kJ. In the presence of a catalyst Eacat is 110kJ.
The activation energy is the energy needed to go from the reactants to the transition state, i.e. up the hill.
Since the activation energy in the forward direction is 128 kJ (from the reactants to the transition state) and ...
It finds the enthalpy of reaction given the activation energies of the reaction and the reverse one. The solution is detailed and has a '5/5' rating.