Equilibrium and Acid - Base Reactions
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1. The Ka for HF is 6.6 x 10^-4. What percentage of the HF is ionized if 5 grams are dissolved in 1 liter of water?
2, Assume an indicator, HA, has a Ka od exactly 10^-7. This means that at pH = 7 there are equal numbers of molecules of both colors. What is the ration of colors at pH values of 7.2 and 8.0?
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Solution Summary
This solution calculates the percentage of HF that can be ionized given number of grams.
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Equilibrium and Acid - Base Reactions
1. The Ka for HF is 6.6 x 10^-4. What percentage of the HF is ionized if 5 grams are dissolved in 1 liter of water?
Solution:
First, we calculate the number of moles of HF.
Second, we set up an ice table.
HF ...
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