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Equilibrium and Acid - Base Reactions

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1. The Ka for HF is 6.6 x 10^-4. What percentage of the HF is ionized if 5 grams are dissolved in 1 liter of water?

2, Assume an indicator, HA, has a Ka od exactly 10^-7. This means that at pH = 7 there are equal numbers of molecules of both colors. What is the ration of colors at pH values of 7.2 and 8.0?

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Solution Summary

This solution calculates the percentage of HF that can be ionized given number of grams.

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Equilibrium and Acid - Base Reactions

1. The Ka for HF is 6.6 x 10^-4. What percentage of the HF is ionized if 5 grams are dissolved in 1 liter of water?

Solution:

First, we calculate the number of moles of HF.

Second, we set up an ice table.

HF ...

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