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Reduction Mechanisms for Formadehyde

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Given the following:
methanoic acid (CH2O2) + heat + reduction = CH2O (formaldeyhde vapor)

ethanoic acid (C2H4O2) + heat + reduction = CH3O2 (acetaldehyde vapor)

1) Is it reasonable to assume that these aqueous organic acids when heated to vapor will in fact lose an oxygen and convert to formaldehyde and acetaldehyde vapor?

2) Under these similar circumstances, how is methanol created....I've seen in some kinetics work that I've done that:

formaldehyde + water = methylene glcol which in turn can be reduced to methanol?? I've also seen where the reaction is to ethylene glycol and then reduced to methanol??? Which is it and can you explain?

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Reduction Mechanisms for Formadehyde are discussed as well as formation of ethylene glycol.

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I can reason the following:

methanoic acid (CH2O2) + heat + reduction = CH2O (formaldeyhde vapor)

ethanoic acid (C2H4O2) + heat + reduction = CH3O2 (acetaldehyde vapor)

1) Is it reasonable to assume that these aqueous organic acids when heated to vapor will in fact lose an oxygen ...

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