the work done against friction

Related BrainMass Solutions

• Concept of negative work done by friction.

  Work done by the friction means that the work is being done against the friction and the applied force F is doing (positive) work to move body against friction. The solution explains how the work done by the friction can be negative.

• Inclined plane: How far up a plane will block go; how fast when it slides to the bottom?

  therefore work done by block against friction : Wf = mu*m*g* cos(theta) * s where mu = friction coeff = 0.25 work done against gravity: Wg = m*g*h here h is vertical displacement = s*sin(theta) therefore, Wg = m*g*s*sin(theta) total work done

• Jack Screw Friction Force

  against friction force (f).

• Initial kinetic energy of the object

  What is the work does against friction when moving from A to B and the initial speed of the body? What is the work done against friction when the body moves from A to B and back to A and the speed when it returns to A?

• Conservation of Energy in a Roller Coaster

  gravitational acceleration g = 9.8 m/s^2 average friction force f = mg/5 work done against friction force = f*s = mg*55/5 = 11mg By energy law, initial K.E. + P.E. = final K.E. + work done against friction force => (1/2)*m*u^2 + m*g*h1 = (1/

• Physics around an Object Towed up and Incline

  work done by the friction force, wf = -f*s where, f= friction force = 25.46 N; s = displacement along the plane = 10 m -ve sign because of oppsite directions of s and f. => wf = -25.46*10 = -254.6 J (-ve sign shows that work is done against

• Coefficient of Kinetic Friction Between Football Uniforms and Astroturf After a Head-On Collision

  If they slide a distance s, work done against friction force: W = mu*m*g*s mu = 0.35 m = 200 kg g = 9.8 m/s^2 s = ?

• Dynamics: Block attached to spring on incline with friction

  Against the friction force (negative) The work done by the force F is given by W1 = F*s = F (3/2)  = 3F/2 The work done by the friction will be W2 = FFriction*s = - N*s = - W cos *3/2 [As N = W cos ] Hence the total work done

• Man on ice sheet: Can he reach solid land by throwing the rock; how long will it take?

  therefore, work done against friction force: Wf = mu*m*g*s where mu = coeff. of friction between ice and man= 0.03 g= gravitational acceleration = 9.8 m/sec^2 s= displacement to be calculated.