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Electrostatic Forces and Movement of Charged Particles

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Please show all work and diagrams plus equations used to solve problem. Thanks!

1) Particles 1, with charge q1 and 2, with a charge q2 are on the x axis, with particle 1 at x = a with and particle 2 at x=-2a. For the net force on a third charges particle, at the origin to be zero q1 and q2 must be related by q2=:
(answer B, but explain)
a) 2q1
b) 4q1
c) -2q1
d) -4q1
e) -q1/4

2) A particle with charge Q is on the y axis a distance a from the origin and a particle with charge q is on the x axis a distance d from the origin. The value of d for which the x component of the force on the second particle is the greatest is:
(e is answer - why)
a) 0
b) a
c) SQRT 2a
d) a/2
e) a/ SQRT 2

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Solution Summary

The solution provides step-by-step calculations with diagrams for questions involving the concepts of electrostatic forces between charged particles.

Solution provided by:
Changping Wang, MA
Education
  • BSc , Wuhan Univ. China
  • MA, Shandong Univ.
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  • "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
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  • "Thank you so much for all of your help!!! I will be posting another assignment. Please let me know (once posted), if the credits I'm offering is enough or you ! Thanks again!"
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