Block Sliding down a frictionless plane at an angle
A 4.0 kg block is released from rest at the top of a frictionless plane of length 8.0 m that is inclined at an angle of 15° to the horizontal. A cord is attached to the block and trails along behind (assume the cord is massless). When the block reaches a point 5.0 m along the incline from the top, someone grasps the cord and exerts a constant tension parallel to the incline. The tension is such that the block just comes to rest when it reaches the bottom of the incline. (The person's force is nonconservative!) What is this constant tension? Solve the problem twice, once using work and energy and again using Newton's laws and constant acceleration kinematics.
Please solve numerically to find the answer. Please show all work for both ways of solving. Thanks.
$2.19 
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Active since 2003
Responses 828
"Hello there, I have been going through some of my past work, and I seem to still be stuck on qu 3 ( A ball is thrown etc) can this be done using quadratic equation ?"
"Thank you so much, now I know how to do the wrap around of the numbers"
"OK. Thanks. I kinda get it. are the => symbols like an arrow?"
"Thanks could you please, clearly explain your reasoning and your steps. Please, highlight the numeric answers (just the answers). Thank You"
"thanks"