Electromagnetic Induction of Conducting Loop
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Solution Summary
The expert examines the electromagnetic induction of conducting loops.
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A) Area of the circular loop = pi x r^2 = 3.14 x 0.024^2 = 18 x 10^-4 m^2
Initial flux linking the loop = Magnetic flux density x Area of the loop = 3 x 18 x 10^-4 = 54 x 10^-4 webers
Final flux = 2 x 54 x 10^-4 = 108 x 10^-4 webers
Change in flux = Final ...
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