# Write the Equation of a Line Given : Two Points; Slope and a Point; A Point and a Perpendicular Line

WRITING AN EQUATION FOR THE LINE CONTAINING THE INDICATED POINTS:

1. (0,0) AND (3, 30)
2. (-4, -4) AND (-3, -3)
3. (-6, -6) AND (-3, 1)
4. (4, -8) AND (3, -6)
5. ( -1/2, 7) AND -4, 1/2)
6.(-9, 1) AND (-1/2, 1)

Those are the types of problems I am having trouble in writing equations containing indicated points. How do I do them correctly?

WRITING AN EQUATION IN SLOPE-INTERCEPT FORM FOR THE LINE THAT HAS THE INDICATED SLOPE, M, AND CONTAINS THE GIVEN POINT.

1. m= 1/2, (8, 1)
2. m= -4, (5, -3)
3. m= 0, (2, 3)
4. m= 4, (9, -3)
5. m= 1/5 (8, -2)

If you could explain how to do those I'd appreciate it.

WRITING AN EQUATION IN SLOPE-INTERCEPT FORM FOR THE LINE THAT CONTAINS THE GIVEN POINT AND IS PARALLEL TO THE GIVEN LINE

1. (5, -3) y= 4x + 2
2. (-6, 2), y= -2/3x - 3
3. (4, -3), 3x + 4y = 8
4. (4, -3), -4x + y = -7

WRITING AN EQUATION IN SLOPE-INTERCEPT FORM FOR THE LINE THAT CONTAINS THE GIVEN POINT AND IS PERPENDICULAR TO THE GIVEN LINE

1. (-2, 5), y+ -2x + 4
2. (1, -4), y= 3x - 2
3. (8, 5), y= x + 2
4. (0, -5), y = x - 5
5. (2, 5), 6x + 2y =24
6. (3, -1), 12x + 4y = 8
7. (-2, 4), x -6y = 15
8. (5, -2), 2x - 5y =15

How do I write an equation for a line that is prependicular to 2x + 5y = 15 at the y intercept? How do I write an equation that is perpendicular to the line x-3y = 9 in the x-intercept?

If you could take me through all of these problems in a step-by-step process, I'd appreciate it, thank you.

Solution Summary

Equations of lines are found given : Two Points; Slope and a Point or A Point and a Perpendicular Line. The solution is detailed and well presented.

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