Find the inverse Laplace transform of (s^3+s^2+2/s) / [s^2(s^2+3s+2)]
Using this (or otherwise), Find the solution of the equation y"+3y'+2y = 1-t
Find the transform of the following functions:
f(t) = (1+t^2)[u(t-1)-u(t-2)] where u(t) is the unit step function.
f(t) = sin(t) for 0
The solution shows how (among other things) to utilize partial fractions and inverse transform to solve a non-homogeneous differential equation.