Mathematics Homework Solutions
Problem
#44690

Linear Programming with Excel

Acme estimates it costs $1.50 per month for each unit of this appliance carried in inventory (estimated by averaging the beginning and ending inventory levels each month).  Currently, Acme has 120 units in inventory on hand for the product. To maintain a level workforce, the company wants to produce at least 400 units per month. They also want to maintain a safety stock of at least 50 units per month. Acme wants to determine how many of each appliance to manufacture during each of the next four months to meet the expected demand at the lowest possible total cost... see attachment for remainder of problem.                                        

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a.doc
Acme estimates it costs $1.50 per month for each unit of this appliance
carried in inventory (estimated by averaging the beginning and ending
inventory levels each month). Currently, Acme has 120 units in
inventory on hand for the product. To maintain a level workforce, the
company wants to produce at least 400 units per month. They also want to
maintain a safety stock of at least 50 units per month. Acme wants to
determine how many of each appliance to manufacture during each of the
next four months to meet the expected demand at the lowest possible
total cost.

For the following problem, I need the following typed. Must also include
copy of Excel Solver Screenshot used to solve the model

a) Formulate LP problem b) Create spreadsheet model (show screen shot
from computer, using Excel/Solver. Must actually be a screenshot of the
entire table, not just the data from the table)

c) What is optimal solution?

d) How much money could Acme save if they were willing to drop the
restriction about producing at least 400 units per month?

Month

1 2 3 4

Demand 420 580 310 540

Production Cost $49.00 $45.00 $46.00 $47.00

Production Capacity 500 520 450 550



Solution Summary

This shows how to complete a linear programming problem, including an excel solver spreadsheet model.

Solution
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    • solution(b).xls
    • solution(d).xls
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