Proof : If O is an interior point of triangle ABC prove that OA+OB+OC...

If O is an interior point of triangle ABC prove that OA+OB+OC a- is greater than 1/2 (perimeter of triangle ABC) b- is less than the perimeter of triangle ABC

Parallelogram Proof : BE is a median of triangle ABC. The line through C and the midpoint H of BE meets AB at F. prove that AF/FB=2.

BE is a median of triangle ABC. The line through C and the midpoint H of BE meets AB at F. prove that AF/FB=2. You must use a parallogram proof Hint: extend BE to 3/2 of its length

Proof : Given triangle ABC where BC=CD prove that if x>y then y is less than z

Given triangle ABC where BC=CD prove that if x>y then y is less than z Please see the attached file for the fully formatted problems.

Hinge Theorem : Prove the first half of the open-jaw inequality where the point G lies inside triangle DEF i.e. show that if x less than y => AC < DF.

Prove the first half of the open-jaw inequality where the point G lies inside triangle DEF i.e. show that if x less than y => AC < DF. Please see the attached file for the fully formatted problems.

Proof : Use the side-angle inequality to show that in triangle ABC if the internal bisector of angle A meets BC at D and AB>AC , then DB>DC.

Use the side-angle inequality to show that in triangle ABC if the internal bisector of angle A meets BC at D and AB>AC , then DB>DC.

Convex Quadrilateral : ABCD is a convex quadrilateral and F and H are the midpoint of BC and AD respectively. If AC cuts FH at the midpoint K of FH show that [ABC]=[ADC].

ABCD is a convex quadrilateral and F and H are the midpoint of BC and AD respectively. If AC cuts FH at the midpoint K of FH show that [ABC]=[ADC]. ([] = area)

ABCD is a convex quadralteral as shown in document and E,F,G,H are midpoints of AB,BC,CD,DA. EG cuts FH at K prove that [AEKH]+[CGKF]=[BFKE]+[DHKG]

ABCD is a convex quadralteral as shown in document and E,F,G,H are midpoints of AB,BC,CD,DA. EG cuts FH at K prove that [AEKH]+[CGKF]=[BFKE]+[DHKG]

Proof : Given the figure in document with 3BF=2FC , AE=2EF and [DEF]=1 a- FIND [DFC] b-FIND AC/AD

Given the figure in document with 3BF=2FC , AE=2EF and [DEF]=1 a- FIND [DFC] b-FIND AC/AD [ ]=area

Proof

ABCDEF is a convex hexagon with side AB parallel to CF side CD parallel to BE and side EF parallel to AD prove that [ACE]=[BDF] as shown in document (attached).

Proof : Given the figure in document with D=midpoint of AC and E = midpoint of BD a-find BC/BF b-find [AEB] if [BEF]=1

Given the figure in document with D=midpoint of AC and E = midpoint of BD a-find BC/BF b-find [AEB] if [BEF]=1