Referring to the attached document:
Determine the voltage drop (from top to bottom) across the 16 ohm resistor the circuit shown.
My Answer:
16Ohm/(16Ohm+8Ohm)*12V=8V
Additionally:
Referring to the circuit shown, determing the voltage drop across the 4 ohm resistor:
My Answer:
4Ohms/(4Ohms+8Ohms)*12V=4/12*12V=4V
Additionally:
What is the voltage V?
My Answer:
I=12/[(16*8)/(16+8)+(4*8)/(4+8)]=12/(5.33+2.66)=12/8=1.5A
V=1.5A*[4/(4+8)+16/(8+16)]
1.5A*(.3333+.6667)=
1.5A*1Ohm=1.5V
Final answer: 1.5V