For the reaction:
3 NO2 (g) + H2O (l) ( 2 HNO3 (aq) + NO (g), ΔH = –140 kJ.
Given ΔH°f of NO2 (g) = 34 kJ/mol, ΔH°f of H2O (l) = –286 kJ/mol,
ΔH°f of NO (g) = 90 kJ/mol.
Calculate ΔH°f of HNO3 (aq), in kJ/mol.
–197
–182
–212
–207
–192
