Chemistry Homework Solutions
Problem
#6387

Calculating the activation energy given the rate constant and change in temperature.

For a certain reaction, the rate constant doubles when the temperature is increased from 25 degrees Celsius to 41 degrees Celsius. What is the activation energy for this reaction? (R=8.31J/mol.K)

Solution
What is this?
By OTA - Overall OTA Rating
Departed OTA
Purchase Cost Now
$2.19 CAD (was ~$3.99)
Included in Download
  • Plain text response
Why you can trust BrainMass.com
  • Your Information is Secure
  • Best Online Academic Help Service
  • Students find real academic Success
Related Solutions
  • Activation Energy and the Arrhenius Equation - Given that the rate constant is 4.0×10^−4 at 25.0 degrees C and that the rate constant is 2.6×10^−3 at 42.4 degrees C, what is the activation energy in kilojoules per mole?
  • rate and temprature - The rate of a particular reaction triples when the temprature is increased from 25C to 35C. Calculate the activation energy for this reaction. i got the answer 8.38*10^4 J/mol..But i dont know the ...
  • Calculating the change in the rate constant when temperature is decreased. - For a certain reaction, the activation energy is 52.1kJ/mole. By what ratio will the rate constant change if the temperature is decreased from 175 degrees Celsius to 75 degrees Celsius?
  • Activation energy and rate of reaction - The activation energy of a certain reaction is 76.7 kj/mol. How many times faster will the reaction occur at 62 degrees C than at 5 degrees C?
  • Arrhenius Equation : Finding Activation Energy - The rearrangement of cyclopropane to propene has been studied at various temperatures with the following results. Rate constant, k (s-1) Temperature (K) 3.30 x 10-9 600 2.19 x 10-7 650 7.96 x 10-6 ...
Browse