Calculating the activation energy given the rate constant and change in temperature.
For a certain reaction, the rate constant doubles when the temperature is increased from 25 degrees Celsius to 41 degrees Celsius. What is the activation energy for this reaction? (R=8.31J/mol.K)
Activation Energy and the Arrhenius Equation - Given that the rate constant is 4.0×10^−4 at 25.0 degrees C and that the rate constant is 2.6×10^−3 at 42.4 degrees C, what is the activation energy in kilojoules per mole?
rate and temprature - The rate of a particular reaction triples when the temprature is increased from 25C to 35C. Calculate the activation energy for this reaction.
i got the answer 8.38*10^4 J/mol..But i dont know the ...
Activation energy and rate of reaction - The activation energy of a certain reaction is 76.7 kj/mol. How many times faster will the reaction occur at 62 degrees C than at 5 degrees C?
Arrhenius Equation : Finding Activation Energy - The rearrangement of cyclopropane to propene has been studied at various temperatures with the following results.
Rate constant, k (s-1) Temperature (K)
3.30 x 10-9 600
2.19 x 10-7 650
7.96 x 10-6 ...