The reactants are trans-chalcone and ethyl acetoacetate (in
We are preparing an a,b-unsaturated ketone via Michael and aldol condensation reactions. The reactants are trans-chalcone and ethyl acetoacetate (in ethanol and NaOH). This creates 6-ethoxycarbonyl-3,5-diphenyl-2-cyclohexenone. What I'm wondering is:
Why is it possible to separate the product from sodium hydroxide using acetone?
Could you tell me what is the purpose of this reaction (Michael and aldol condensation reactions), and the stepwise mechanism of the reaction.
Also if we started with 0.24 gr of trans-chalcone , 0.15 gr of ethyl acetoacetate what would be the theoretical yield ?
The solution provides detailed explanations and answer, including reaction mechanism and drawings, for the problem.
This answer includes:
- Plain text
- Cited sources when necessary
- Attached file(s)
- michael-aldol mechanism trans-chalcone.doc