# Finding equilibrium constant and delta G

Part 1:
Ammonia can be produced by the reaction of hydrogen gas and nitrogen gas, as shown below:

N2(g) + 3H2(g) &#8594; 2NH3(g)

Given that the standard free energy of formation (&#8710;Gof) of NH3 (g) is -111 kJ/mol at 335 K, calculate the equilibrium constant, K, at this temperature.
To express an answer in exponential notation, use E to indicate the exponent. For example, 3.0 x 103 would be written, 3.0E3.

Part 2:
In the previous question, you had to calculate the the standard Free Energy Change (&#8710;Go) in order to solve for the equilibrium constant, K, for the reaction:

N2(g) + 3H2(g) &#8594; 2NH3(g)

This is the Free Energy measured under standard conditions, when the reaction is started with 1.0 M of each of the three gases present. Calculate the non-standard Free Energy change (&#8710;G) at 298 K, given the following non-standard initial concentrations of the three gases (Answer in kJ).
&#8710;Gfo = -16.6 kJ/mol for NH3 (g) at 298 K

initial concentration (M)
N2 1.0
H2 0.09
NH3 4.1

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Jayant Kumar, MBA

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MBA, Indian Institute of Finance

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